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Re: [CPROG] 64 bit little endian



Tak, det vil jeg prøve !

Mvh.
Martin


> sslug@sslug wrote:
> [snip]
>>
>> En del er denne data er et 8x8 bytes eller 64 bits (little endian)
>> timestamp:
>> 7a 11 21 46 f6 05 00 00
>>
>> Spørgsmålet er så endelig - Hvordan arbejder jeg nemmest med dette
>> timestamp og får dette konverteret til et læseligt tal?
>> Timestamp'et skulle også gerne på en eller anden måde ende i en struct?
>>
>
> union my_union
>    {
>    int64_t integer;
>    unsigned char[8] bytes;
>    } my_time;
>
> memcpy(my_time.bytes, 'en pointer til data', 8);
>
> printf("64-bit time: %jd\n", my_time.integer);
>
>
> Med venlig hilsen
> Egon Andersen
>
>



 
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